Question

x+x/2=-12     x+x/3=8   x+x/7=-8   x+x/2=-6

Answer 1

$x+ frac{x}{2} =-12 \ \ frac{2x+x}{2} =-12 \ \ frac{3x}{2} =-12 \ \ 3x=-24 \ \ x=-8$


$x+ frac{x}{3} =8 \ \ frac{3x+x}{3} =8 \ \ frac{4x}{3} =8 \ \ 4x=24 \ \ x=6$


$x+ frac{x}{7} =-8 \ \ frac{7x+x}{7} =-8 \ \ frac{8x}{7} =-8 \ \ 8x=-56 \ \ x=-7$


$x+ frac{x}{2} =-6 \ \ frac{2x+x}{2} =-6 \ \ frac{3x}{2} =-6 \ \ 3x=-12 \ \ x=-4$

Answer 2

х+х/2=-12 |•2
2х+х=-24
3х=-24
х=-8

х+х/3=8 |•3
3х+х=24
4х=24
х=6

х+х/7=-8|•7
7х+х=-56
8х=-56
Х=-7

х+х/2=-6|•2
2х+х=-12
3х=-12
Х=-4