Question

$left { {{x+y=-2} atop { y^{2}-3x=6 }} right.$

Answer 1

$left { {{x+y=-2} atop { y^{2}-3x=6 }} right. \ x=-y-2 \ y^2-3(-y-2)=6 \ y^2+3y+6=6 \ y^2+3y=0 \ y(y+3)=0 \ y_1=0 \ y_2=-3 \ x_1=-0-2=-2 \ x_2=-(-3)-2=1$
Ответ: (-2; 0); (1; -3)