Question

(3-4sinx)*(3+4cosx)=0

Answer 1

(3-4sinx)·(3+4cosx)=0

3-4sinx = 0

4sinx = 3

sinx = 0,75

х = (-1)^k arcsin(0.75) + πk    k∈Z

3+4cosx = 0

4cosx = -3

cosx = -0.75

x = ±(π - arccos 0.75) + 2πk    k∈Z