Question

помогите решить уравнение!

Answer 1

(√3 · ctgπx - 1)·(arccos(x/3)² - π/3) = 0

1) √3 · ctgπx - 1 = 0

ctgπx= 1/√3

πx = π/3 + πn

x₁ = 1/3 + n, n∈Z

2) arccos(x/3)²- π/3 = 0

arccos(x/3)² = π/3

x²/9 = cos π/3

x²/9= 1/2

x² = 9/2

x₂ = 1.5√3