Question

решите систему уравнений методом
замены переменной 1) х^2у^2-5ху=-6 х
+у=3

Answer 1

$left { {{x^{2}y^{2} -5xy =-6} atop {x+y=3}} right. left { {{x^{2}y^{2} -5xy =-6} atop {y=3-x}} right. left { {{x^{2} cdot (3-x)^{2} -5x cdot (3-x) =-6} atop {y=3-x}} right. \ left { {{x^{2} cdot (9-6x+x^{2})-15x+5x^{2}=-6} atop {y=3-x}} right. left { {{9x^{2}-6x^{3}+x^{4}-15x+5x^{2}+6=0} atop {y=3-x}} right.\left { {{x^{4}-6x^{3}+14x^{2}-15x+6=0} atop {y=3-x}}right. left { {{(x^{2}-3x+2) cdot (x^{2}-3x+3)=0} atop {y=3-x}} right$$left { {{(x-1) cdot (x-2) cdot (x^{2}-3x+3)} atop {y=3-x}} right. left { { left {{x_{1}=1;} atop {x_{2}=2;}} right. } atop { left {{y_{1}=2;} atop {y_{2}=1}} right. }} right. \x^{2}-3x+3=0; - ; net; resheniya$

Ответ: (1;2),(2;1)

Answer 2

х^2-у^2-5ху=-6 минус между х^2 и у^2

Answer 3

Ну ты даёшь.

Answer 4

http://znanija.com/task/6418402