Question

(3lg3+lg12)/(lg2+lg9)

Answer 1

$frac{(3lg3+lg12)}{(lg2+lg9)}=frac{(lg3^3*12)}{(lg2*9)}=frac{lg324}{lg18}=log_1_8 324=log_1_8 324=2$

Answer 2

нуу)))

Answer 3

спасибоо