Question

Быстрееее!!!!Надо 3(в),5

Answer 1

$a^{3}-125b^{3}=a^{3}-5^{3}b^{3}=(a-5b)(a^{2}+5ab+b^{2})$
$frac{3.8(8.2^{2}-1.8^{2})}{1.9(5.3^{2}-4.7^{2})}= frac{2(8.2-1.8)(8.2+1.8)}{(5.3-4.7)(5.3+4.7)}= frac{2*6.4*10}{0.6*10}= frac{2*6.4}{0.6}= frac{6.4}{0.3}= frac{64}{3}$

Answer 2

да

Answer 3

всё