Question

(x+1)(2y-1)=0 и 2y^2+x-y=5

Answer 1

(x+1)(2y-1)=0 и 2y^2+x-y=5

(x+1)(2y-1)=0,2y^2-y+x=5

x=5

2y=1

y=2

 2y=-3

 x=-1

Ответ:x = -1, y = 2; x = -1, y = -3/2; x = 5, y = 1/2;