Question

Решить систему уравнений:

{
x+y=2,2
x^2+xy+y^2=8.

Answer 1

x+y=2,2
x^2+xy+y^2=8.

x=2,2-y
(2,2-y)^2+(2,2-y)y+y^2=8.

x=2,2-y
4.84-4.4y+y^2+2.2y-y^2-8=0

x=2,2-y
2.2y-8=8-4.84

x=2,2-y
y=1.44

x=2.2-1.44=0.76