Question

(х-1)(x+1)(x^2+1)=6x^2-1 уравнение

Answer 1

$(x-1)(x+1)(x^{2}+1)=6x^{2}-1\\ (x^{2}-1)(x^{2}+1)=6x^{2}-1\ x^{4}-1=6x^{2}-1\ x^{4}-6x^{2}=0\ x^{2}(x^{2}-6)=0\ x^{2}=0\ x_{1}=0\ x^{2}-6=0\ x^{2}=6\ x_{2}=sqrt{6}\ x_{3}=- sqrt{6}$