Предмет: Алгебра, автор: katyapash

Из пункта А в пункт В, расстояние между которыми 4 км. одновременно выходит пешеход и выезжает велосипедист. велосипедист доезжает до В, сразу поворачивает обратно и встречает пешехода через 24 мин после своего выезда из А. Определите скорость пешехода и велосипедиста, если известно, что велосипедист проезжает в час на 10 км больше, чем проходит пешеход.

Ответы

Автор ответа: andresm1
0

Расстояние между пунктами А и В    S = 4 км 

Время движения t = 24 мин = 24/60 (час)  = 0,4 час.

Обозначим скорость пешехода х (км/ч)

Тогда скорость велосипедиста (х + 10) (км/ч)

За время t = 0,4 ч пешеход пройдет Sп = 0,4*х

За время t = 0,4 ч велосипедист проедет   Sв = 0,4*(х+10)

С другой стороны , путь велосипедиста равен Sв = S+(S-Sп) = 4+(4-0,4х) = 8-0,4х

Тогда 0,4*(х+10) = 8 - 0,4х

0,4х + 4 = 8 - 0,4х

0,8х = 4

х = 4/0,8 = 5 (км/ч) - скорость пешехода

Тогда скорость велосипедиста 5+10 = 15 км/ч

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