Question

(√(34) + √(46))^2 / 20 + √(391)

Answer 1

$( sqrt{34} + sqrt{46} )^2/20+ sqrt{391} =( 34 +2 sqrt{1564}+ 46 )^2/20+ sqrt{391}=$
$=( 80 +4sqrt{391})/20+ sqrt{391}=4+ frac{sqrt{391}}{5}+sqrt{391}=4+frac{sqrt{391}+5sqrt{391}}{5}=$
$=4+frac{6sqrt{391}}{5}=4+1.2sqrt{391}$