Question

Найдите производную функции

Answer 1

$((8x-15)^6)`=6(8x-15)^5*(8x-15)`=6*8(8x-15)^5=\=48(8x-15)^5\\(sqrt{3-2x})`=sqrt{-2}{sqrt{3-2x}}\\(sin(4x+pi /6)`=4cos(4x+pi /6)\\(frac{1}{(1-3x)^2})`=-frac{-3(-2)}{(1-3x)^3}=frac{-6}{(1-3x)^2}$

Answer 2

б)$(3-2x) ^ frac{1}{2} = frac{1}{2} *(3-2x)^- frac{1}{2} *(-2) = - frac{1}{ sqrt{3-2x} }$
г) $(1-3x) ^{-1} =-1*(1-3x) ^{-2} *(-3)= frac{3}{(1-3x) ^{2} }$