Question

4m²-52nm+169n²         b²+24b+144      c²n⁴-144     25m¹⁰-10m⁵n²+n⁴                    d⁶-225       разложить на множители

Answer 1

$(2m)^{2}-2*2*13nm+(13n)^{2}=(2m-13n)^{2} \ b^{2}+2*12b+12^{2}=(b+12)^{2} \ (cn^{2})^{2}-12^{2}=(cn^{2}-12)(cn^{2}+12) \ (5m^{5})^{2}-2*5m^{5}n^{2}+(n^{2})^{2}=(5m^{5}-n^{2})^{2} \ (d^{3})^{2}-15^{2}=(d^{3}-15)(d^{3}+15)$