Question

1/(2-x)-1=1/(x-2)-(6-x)/(3x^2-12)

Answer 1

ОЗ 3(х-2)(х+2)≠0⇒х≠2 и х≠-2
-3(х+2)-(3х²-12)=3(х+2)-(6-х)
-3х-6-3х²+12-3х-6+6-х=0
-3х²-7х+6=0
D=49+4*18=49+72=121 √D=11
x1=(7-11)/-6=2/3
x2=(7+11)/-6=-3