Question

log_(1/7)(4x+1)<-2

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Answer 1

$log_{frac{1}{7}}(4x+1)<-2|4x+1>0, 4x>-1, x>-frac{1}{4}\\log_{frac{1}{7}}(4x+1)<log_{frac{1}{7}}49\\4x+1>49\\4x>48|:4\\x>12\\x in (12;+infty)$