Question

помогите!!!!!  решите неравенство tg(2x-π/3)<√3/3

Answer 1

$tg(2x-frac{pi}{3})<frac{sqrt3}{3}$

$-frac{pi}{2}+pi n<2x-frac{pi}{3}<frac{pi}{6}+pi n\\-frac{pi}{6}+pi n<2x<frac{pi}{2}+pi n\\-frac{pi}{12}+frac{pi n}{2}<x<frac{pi}{4}+pi n,ninZ$