Question

(x+3)(3x-2)5 (7-x)3 (5x+8)4<или=0

Answer 1

$(x+3)(3x-2)^5(7-x)^3(5x+8)^4 leq 0\\(x+3)(3x-2)^5(x-7)^3(5x+8)^4 geq 0\\x+3=0,; 3x-2=0,; x-7=0,; 5x+8=0\\x=-3,; x=frac{2}{3},; x=7,; x=-frac{8}{5}=-1,6\\- - - - -[-3]+ + + +[-1,6]+ + + +[frac{2}{3}]- - - -[7]+ + + +\\xin [-3;frac{2}{3}]U[7;+infty)$