Question

решите на множестве R систему неравенства:
(9x+9)(x-4)>9x²+x+5=
2x-3-(x-3)≤5=

Answer 1

$left { {{(9x+9)(x-4) > 9x^2+x+5} atop {2x-3-(x-3)leq5}} right.\ left { {{9x^2-27x-36 > 9x^2+x+5} atop {2x-3-x+3leq5}} right.\ left { {{9x^2-27x-36-9x^2-x-5>0} atop {xleq5}} right.\ left { {{-28x-41>0} atop {xleq5}} right.\ left { {{-28x>41} atop {xleq5}} right.\ left { {{x<-frac{41}{28}} atop {xleq5}} right.\ x<-frac{41}{28}$