Question

РЕШИТЕ СРОЧНО ∫ (4sin(3x - 2) * cos(3x - 2)+ 3x -2) dx

Answer 1

$intlimits {(4sin(3x-2)cos(3x-2)+3x-2)} , dx = intlimits {2sin(6x-4)+3x-2} , dx= \ \ = intlimits{2sin(6x-4)}dx+intlimits{3x}dx-intlimits{2}dx=- frac{cos(6x-4)}{3}+ frac{3}{2}x^2-2x= \ \ = frac{1}{2} x(3x-4)- frac{1}{3} cos(6x-4)$

Answer 2

ЕТО ПОЛНЫЙ ОТВЕТ?

Answer 3

да