2Al + 6HCl= 2AlCl3 + 3H2 + 623kJ Find how much energy is released if 534g of AlCl3 is produced
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Ответы
Ответ:
Объяснение:To find out how much energy is released if 534g of AlCl3 is produced, we can use the balanced chemical equation and the given enthalpy change (∆H) of the reaction.
The balanced chemical equation for the reaction is:
2Al + 6HCl → 2AlCl3 + 3H2 + 623 kJ
From the balanced equation, we can see that 2 moles of AlCl3 are produced for every mole of AlCl3. This means that the molar mass of AlCl3 is needed to determine the number of moles produced from the given mass.
The molar mass of AlCl3 can be calculated as follows:
Al: 26.98 g/mol
Cl: 35.45 g/mol x 3 = 106.35 g/mol
Molar mass of AlCl3 = 26.98 g/mol + 106.35 g/mol = 133.33 g/mol
Now, we can calculate the number of moles of AlCl3 produced using the given mass:
Number of moles = Mass / Molar mass
Number of moles = 534 g / 133.33 g/mol ≈ 4 moles
Since the reaction releases 623 kJ of energy per 2 moles of AlCl3, we can calculate the energy released for the given amount:
Energy released = (4 moles / 2 moles) x 623 kJ
Energy released = 2 x 623 kJ
Energy released = 1246 kJ
Therefore, if 534g of AlCl3 is produced, approximately 1246 kJ of energy will be released.