Question

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Answer 1

Ответ:

1 - Б, 2 - В, 3 - А

Объяснение:

$\frac{\sqrt{a}+5 }{25-a}=\frac{\sqrt{a}+5 }{(5+\sqrt{a})(5-\sqrt{a})}=\frac{1}{5-\sqrt{a}}=-\frac{1}{\sqrt{a}-5}$

$\frac{5-\sqrt{a} }{a-5\sqrt{a} } =-\frac{\sqrt{a}-5 }{\sqrt{a}(\sqrt{a}-5) } =-\frac{1}{\sqrt{a} }$

$\frac{\sqrt{a}-5 }{a-10\sqrt{a}+25 } =\frac{\sqrt{a}-5 }{(\sqrt{a}-5) ^{2} } = \frac{1}{\sqrt{a}-5 }$