Question

ПОМОГИТЕ ПОЖАЛУЙСТА МНЕ!!!!!!!!!!!!

Answer 1

Ответ:

$\frac{x + 7}{x + 9} + ( \frac{x + 7}{ {x}^{2} + 81 - 18x} + \frac{x + 5}{ {x}^{2} - 81 } )( \frac{x - 9}{x + 8} {)}^{2} = \frac{x + 7}{x + 9} + ( \frac{x + 7}{(x - 9 {)}^{2} } + \frac{x + 5}{(x - 9)(x + 9)} )( \frac{x - 9}{x + 3} {)}^{2} = \frac{x + 7}{x + 9} + \frac{(x + 7)(x + 9) + (x + 5)(x - 9)}{(x + 9)(x - 9 {)}^{2} } \times \frac{(x - 9 {)}^{2} }{(x + 3 {)}^{2} } = \frac{x + 7}{x + 9} + \frac{ {x}^{2} + 16x + 63 + {x}^{2} - 4x - 45 }{(x + 9)(x - 9 {)}^{2} } \times \frac{(x - 9 {)}^{2} }{(x + 3 {)}^{2} } = \frac{x + 7}{x + 9} + \frac{2( {x}^{2} + 6x + 9) \times (x - 9 {)}^{2} }{(x + 9)(x - 9 {)}^{2} \times (x + 3 {)}^{2} } = \frac{x + 7}{x + 9} + \frac{2(x + 3 {)}^{2} }{(x + 9)(x + 3 {)}^{2} } = \frac{x + 7}{x + 9} + \frac{2}{x + 9} = \frac{x + 7 + 2}{x + 9} = \frac{x + 9}{x + 9} = 1$