Question

Сделать задание на python с помощью tkinter

Answer 1

Ответ:

from tkinter import *

root = Tk()

l1 = Label(text='')

l1.pack()

e1 = Entry(width=19,justify=CENTER)

e1.pack()

k=['','#ff0000','#ff7d00','#ffff00','#00ff00','#007dff','#0000ff','#7d00ff']

a=['','красный', 'оранжевый', 'желтый', 'зеленый', 'голубой', 'синий', 'фиолетовый']

def i1():

   e1.delete(0,END)

   e1.insert(0, k[1])

   l1.config(text=a[1])

b1 = Button(bg='#ff0000', width=15, command=i1)

b1.pack()

def i2():

   e1.delete(0,END)

   e1.insert(0, k[2])

   l1.config(text=a[2])

b2 = Button(bg='#ff7d00', width=15, command=i2)

b2.pack()

def i3():

   e1.delete(0,END)

   e1.insert(0, k[3])

   l1.config(text=a[3])

b3 = Button(bg='#ffff00', width=15, command=i3)

b3.pack()

def i4():

   e1.delete(0,END)

   e1.insert(0, k[4])

   l1.config(text=a[4])

b4 = Button(bg='#00ff00', width=15, command=i4)

b4.pack()

def i5():

   e1.delete(0,END)

   e1.insert(0, k[5])

   l1.config(text=a[5])

b5 = Button(bg='#007dff', width=15, command=i5)

b5.pack()

def i6():

   e1.delete(0,END)

   e1.insert(0, k[6])

   l1.config(text=a[6])

b6 = Button(bg='#0000ff', width=15, command=i6)

b6.pack()

def i7():

   e1.delete(0,END)

   e1.insert(0, k[7])

   l1.config(text=a[7])

b7 = Button(bg='#7d00ff', width=15, command=i7)

b7.pack()

root.mainloop()

Объяснение:

фото