Предмет: Алгебра, автор: mogdalinamarshak

4x - (8x ^ 2)/(2x - 3)​

Ответы

Автор ответа: rewasiv
1

Ответ:

\frac{-12x}{2x-3}

Объяснение:

4x - \frac{(8x^2)}{(2x-3)} =

\frac{4x(2x-3)}{2x-3} -\frac{8x^2}{2x-3} =

\frac{8x^2-12x-8x^2}{2x-3} =

\frac{-12x}{2x -3}

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