Question

4x - (8x ^ 2)/(2x - 3)​

Answer 1

Ответ:

$\frac{-12x}{2x-3}$

Объяснение:

$4x - \frac{(8x^2)}{(2x-3)} =$

$\frac{4x(2x-3)}{2x-3} -\frac{8x^2}{2x-3}$ =

$\frac{8x^2-12x-8x^2}{2x-3} =$

$\frac{-12x}{2x -3}$