Question

7. Выполните вычитание:

Answer 1

Объяснение:

$\displaystyle\\\frac{a+2}{2a-a^2}-\frac{a+6}{4-a^2}=\frac{a+2}{a*(2-a)} -(-\frac{a+6}{a^2-4} )=-\frac{a+2}{a*(a-2)} +\frac{a+6}{(a+2)*(a-2)} =\\\\=\frac{-(a+2)^2+a*(a+6)}{a*(a+2)*(a-2)} =\frac{-(a^2+4x+4)+a^2+6a}{a*(a+2)*(a-2)} =\frac{-a^2-4a-4+a^2+6a}{a*(a+2)*(a-2)}=\\\\=\frac{2a-4}{a*(a+2)*(a-2)} =\frac{2*(a-2)}{a*(a+2)*(a-2)}=\frac{2}{a*(a+2)}=\frac{2}{a^2+2a}.$