Предмет: Математика, автор: fdxd

2. From a bus station, Yani jogs at 4 m/s due north for 20 minutes,
then at 5 m/s due south for at m/s 15 minutes and finally at 3 m/s
due south for another 10 minutes. Assuming that she jogs along
a straight path, find her final position from the station.
The answer:
Solution:

Приложения:

Ответы

Автор ответа: Chuchmen
0

Ответ:

To find Yani's final position from the bus station, you can break down her motion into three segments and then add up the displacements for each segment.

First segment (jogging north for 20 minutes):

Speed (v1) = 4 m/s

Time (t1) = 20 minutes = 20 * 60 seconds = 1200 seconds

Displacement (d1) = v1 * t1

d1 = 4 m/s * 1200 s = 4800 meters (north)

Second segment (jogging south for 15 minutes):

Speed (v2) = 5 m/s

Time (t2) = 15 minutes = 15 * 60 seconds = 900 seconds

Displacement (d2) = v2 * t2

d2 = 5 m/s * 900 s = 4500 meters (south)

Third segment (jogging south for 10 minutes):

Speed (v3) = 3 m/s

Time (t3) = 10 minutes = 10 * 60 seconds = 600 seconds

Displacement (d3) = v3 * t3

d3 = 3 m/s * 600 s = 1800 meters (south)

Now, let's calculate her net displacement from the bus station:

Net displacement = (d1 - d2 - d3) meters

Net displacement = (4800 m - 4500 m - 1800 m) meters

Net displacement = -1500 meters

Since Yani jogged south after jogging north, her final position from the bus station is 1500 meters to the south of the bus station.

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