Question

помогите пожалуйста ((​

Answer 1

a=$1\frac{7}{15}$:

$\frac{5a-2}{2-3a}=\frac{5*1\frac{7}{15}-2}{2-3*1\frac{7}{15}}=\frac{\frac{22}{3}-2}{2-\frac{22}{5}}=\frac{\frac{22}{3}-\frac{6}{3}}{\frac{10}{5}-\frac{22}{5}}=\frac{\frac{16}{3}}{-\frac{12}{5}}=-\frac{16*5}{3*12}=-\frac{20}{9}$

Аналогично для a=$-1\frac{7}{15}$

$\frac{5a-2}{2-3a}=\frac{5*-1\frac{7}{15}-2}{2-3*-1\frac{7}{15}}=\frac{-\frac{22}{3}-2}{2+\frac{22}{5}}=\frac{-\frac{22}{3}-\frac{6}{3}}{\frac{10}{5}+\frac{22}{5}}=\frac{-\frac{28}{3}}{\frac{32}{5}}=-\frac{28*5}{3*32}=-\frac{35}{24}$