Question

Срочно пятый!!!!!!!!!!

Answer 1

$\displaystyle\bf\\(x+5)(2x+5)-(2x+3)^{2} =16\\\\2x^{2} +5x+10x+25-(4x^{2} +12x+9)=16\\\\2x^{2} +5x+10x+25-4x^{2} -12x-9-16=0\\\\-2x^{2} +3x=0\\\\2x^{2} -3x=0\\\\x\cdot(2x-3)=0\\\\\\\left[\begin{array}{ccc}x=0\\2x-3=0\end{array}\right \\\\\\\left[\begin{array}{ccc}x=0\\2x=3\end{array}\right \\\\\\\left[\begin{array}{ccc}x_{1} =0\\x_{2} =1,5\end{array}\right \\\\\\Otvet \ : \ 0 \ \ ; \ \ 1,5$