Question

пожіть я не знаю як то робити​

Answer 1

$\displaystyle\bf\\1)\\\\\frac{3x-2}{5} =\frac{3}{10} \\\\\\(3x-2)\cdot10=3\cdot 5\\\\(3x-2)\cdot 2=3\\\\6x-4=3\\\\6x=3+4\\\\6x=7\\\\\boxed{x=1\frac{1}{6} }\\\\2)\\\\8+2\cdot(x-1)=3-5\cdot(1-x)\\\\8+2x-2=3-5+5x\\\\2x-5x=3-5-8+2\\\\-3x=-8\\\\\boxed{x=2\frac{2}{3}}$

$\displaystyle\bf\\3)\\\\3\frac{5}{9} -2\frac{1}{6} +4\frac{7}{12} =\Big(3-2+4\Big)+\Big(\frac{5}{9}-\frac{1}{6}+\frac{7}{12} \Big)=\\\\\\=5+\frac{5\cdot4-1\cdot 6+7\cdot3}{36}=5+\frac{20-6+21}{36} =\\\\\\=5+\frac{35}{36} =5\frac{35}{36}$