Question

([x^{2}-1)cosx+(x-1)^{2}sinx] найти производную

Answer 1

([x^{2}-1)cosx+(x-1)^{2}sinx]= cosx^{3}+(х^{2}-2х+1)sinx= cosx^{3}+sinx^{3}-2sinx^{3}+

sinx= -sinx^{3}+cosx^{3} -2cosx^{3}+cosx= -sinx^{3} -  cosx^{3}+cosx