Question

Помогите срочно пожалуйста. Задание на скрине

Answer 1

$1 - \sin {}^{2} ( \alpha ) \cot {}^{2} ( \alpha ) = 1 - \sin {}^{2} ( \alpha ) \times \frac{ \cos {}^{2} ( \alpha ) }{ \sin {}^{2} ( \alpha ) } = \\ = 1 - \cos {}^{2} ( \alpha ) = \sin {}^{2} ( \alpha ) + \cos {}^{2} ( \alpha ) - \cos {}^{2} ( \alpha ) = \\ = \sin {}^{2} ( \alpha )$

$(1 - \cos( \alpha ) )(1 + \cos( \alpha ) ) = 1 - \cos {}^{2} ( \alpha ) = \\ = \sin {}^{2} ( \alpha ) + \cos {}^{2} ( \alpha ) - \cos {}^{2} ( \alpha ) = \sin {}^{2} ( \alpha )$

$\sin( \alpha ) \cos( \alpha ) \tan( \alpha ) = \sin( \alpha ) \cos( \alpha ) \times \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \\ = \sin( \alpha ) \sin( \alpha ) = \sin {}^{2} ( \alpha )$

$\tan( \alpha ) \cot( \alpha ) - \cos {}^{2} ( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \times \frac{ \cos( \alpha ) }{ \sin( \alpha ) } - \cos {}^{2} ( \alpha ) = 1 - \cos {}^{2} ( \alpha ) = \\ = \sin {}^{2} ( \alpha ) + \cos {}^{2} ( \alpha ) - \cos {}^{2} ( \alpha ) = \sin {}^{2} ( \alpha )$

$2 - \sin {}^{2} ( \alpha ) - \cos {}^{2} ( \alpha ) = 2 - ( \sin {}^{2} ( \alpha ) + \cos {}^{2} ( \alpha ) ) = \\=2 - 1 = 1$

Answer 2

Ответ: удачи ☺️☺️☺️☺️☺️

Пошаговое объяснение: