Question

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$(4x - 3) {}^{2} + (3x + 2) {}^{2} \geqslant (5x + 1) {}^{2}$​

Answer 1

Ответ:

x ∈ (-∞;$\frac{6}{11}$]

Объяснение:

$(4x-3)^2+(3x+2)^2\geq(5x+1)^2\\(16x^2-24x+9)+(9x^2+12x+4)\geq25x^2+10x+1\\16x^2-24x+9+9x^2+12x+4\geq25x^2+10x+1\\25x^2-12x+13\geq25x^2+10x+1\\25x^2-12x+13-25x^2-10x-1\geq0\\-22x+12\geq0\\-22x\geq-12\\x\leq\frac{-12}{-22} \\x\leq \frac{6}{11}$