Question

2х³+х²-3х=0

простое задачка​

Answer 1

$2 {x}^{3} + {x}^{2} - 3x = 0 \\ x( {2x}^{2} + x - 3) = 0 \\ x_{1} = 0 \\ 2 {x}^{2} + x - 3 = 0 \\ a =2 \\ b = 1 \\ c = - 3\\ D = {b}^{2} - 4ac = {1}^{2} - 4 \times 2 \times ( - 3) = 1+ 24 = 25\\ x_{2} = \frac{ - 1 - 5}{2 \times 2} = - \frac{6}{4} = - 1.5 \\ x_{3} = \frac{ - 1 + 5}{2 \times 2} = \frac{4}{4} = 1$