Question

буду вам дуже вдячний ​

Answer 1

${x}^{6} = 64 \\ {x}^{6} = {2}^{6} \\ x = ±2$

$\tan(2x) = - \sqrt{3} \\ 2x = \arctan( - \sqrt{3} ) + \pi n = - \frac{\pi}{3} + \pi n, \: n∈Z \\ x = - \frac{\pi}{6} + \frac{\pi n}{2} , n∈Z$