Question

Розв'яжи систему рівнянь методом підстановки:
СРОЧНО! ДАЮ 100 БАЛЛОВ
{3−5(0,2t−2k)=3(3k+2)+2t,
4(k−3t)−(2k+t)=11−2(2k+t)

Answer 1

$\displaystyle\bf\\\left \{ {{3-5(0,2t-2k)=3(3k+2)+2t} \atop {4(k-3t)-(2k+t)=11-2(2k+t)}} \right. \\\\\\\left \{ {{3-t+10k=9k+6+2t} \atop {4k-12t-2k-t=11-4k-2t}} \right. \\\\\\\left \{ {{-t+10k-9k-2t=6-3} \atop {2k-13t+4k+2t=11}} \right. \\\\\\\left \{ {{k-3t=3} \atop {6k-11t=11}} \right.\\\\\\\left \{ {{k=3t+3} \atop {6\cdot(3t+3)-11t=11}} \right. \\\\\\\left \{ {{k=3t+3} \atop {18t+18-11t=11}} \right. \\\\\\\left \{ {{k=3t+3} \atop {7t=11-18}} \right.$

$\displaystyle\bf\\\left \{ {{k=3t+3} \atop {7t=-7}} \right. \\\\\\\left \{ {{k=3\cdot(-1)+3} \atop {t=-1}} \right. \\\\\\\left \{ {{k=-3+3} \atop {t=-1}} \right. \\\\\\\left \{ {{k=0} \atop {t=-1}} \right. \\\\\\Otvet \ : \ (0 \ ; \ -1)$