Question

15B
дар:
-
9x2 – 6ху + у2
3x²-ху
мұнда x=3,y=1

Answer 1

Ответ:

$\frac{ {9x}^{2} - 6xy + {y}^{2} }{3 {x}^{2} - xy } = \frac{(3x - y)^{2} }{x(3x - y) } = \frac{3x - y}{x} \\ x = 3 \: y = 1 \\ \frac{3 \times 3 - 1}{3} = \frac{8}{3} = 2 \frac{1}{3}$