Question

часть 2 задание 1 срочно

Answer 1

$\displaystyle\bf\\\left \{ {{2y-(3y-4) < 6} \atop {5y\geq 3(2y-1)+12}} \right.\\\\\\\left \{ {{2y-3y+4 < 6} \atop {5y\geq 6y-3+12}} \right. \\\\\\\left \{ {{-y < 6-4} \atop {5y-6y\geq -3+12}} \right.\\\\\\\left \{ {{-y < 2} \atop {-y\geq 9}} \right.\\\\\\\left \{ {{y > -2} \atop {y\leq -9}} \right.$

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