Question

СРОЧНО ДАМ 100 БАЛЛОВ!!!ПОДАТЬ У ВИГЛЯДІ СТЕПЕНЯ ​

Answer 1

$n^5*n^3=n^{5+3}=n^8\\c^8:c=c^{8-1}=c^7\\x*x^6=x^{1+6}=x^7\\a^{12}:a^3=a^{12-3}=a^9\\(a+b)^{11}:(a+b)^7=a=(a+b)^{11-7}=(a+b)^4\\(y-2)^5*(y-2)^9=(y-2)^{5+9}=(y-2)^{14}$

Answer 2

${n}^{5} \times {n}^{3} = {n}^{5 + 3} = {n}^{8}$

${c}^{8} \div {c}^{} = {c}^{8 - 1} = {c}^{7}$

$x \times {x}^{6} = x {}^{1 + 6} = {x}^{7}$

${a}^{12} \div {a}^{3} = a {}^{1 2 - 3} = {a}^{9}$

$(a + b) {}^{11} \div (a + b) {}^{7} = (a + b) {}^{11 - 7} = (a + b) {}^{4}$

$(y - 2) {}^{5} \times (y - 2) {}^{9} = (y - 2) {}^{5 +9 } = (y - 2) {}^{14}$