Question

ооочень срочно даю 90 балов​

Answer 1

Ответ:1)

$x^{2} -5x-6\\x^{2} +x-6x-6\\x(x+1)-6(x+1)\\(x+1)(x-6)$

$\frac{2x-10}{x^{2} -3x-10y} \\\frac{2(x-5)}{x^{2} +2x-5x-10} \\\frac{2(x-5)}{x(x+2)-5(x+2)} \\\\\frac{2(x-5)}{x^{2} +2x-5x-10}$

$\frac{2(x-5)}{(x+2)(x-5)} \\\frac{2}{x+2}$

$3x^{4} +16x^{2} -12=0\\3t^{2}+16t-12=0\\ t=-6\\t=2/3\\x1=-\frac{\sqrt{6} }{3} \\x2=\frac{\sqrt{6} }{3}$