Question

Складіть таблицю істинності логічних виразів зі змінними логічного типу a і b:
а) a or a and b
б) a or not a and b
в) a or b or not b
г) (a or not b) and (a or not b)
д) not a or not b
е) a and (not b or a) and b
ж) a and (b or c) not a
з) a or b and c or not b

Answer 1

Ответ:

| a | b | a or a and b |

|---|---|--------------|

| 0 | 0 | 0 |

| 0 | 1 | 0 |

| 1 | 0 | 1 |

| 1 | 1 | 1 |

| a | b | a or not a and b |

|---|---|-----------------|

| 0 | 0 | 0 |

| 0 | 1 | 0 |

| 1 | 0 | 1 |

| 1 | 1 | 1 |

| a | b | a or b or not b |

|---|---|----------------|

| 0 | 0 | 0 |

| 0 | 1 | 1 |

| 1 | 0 | 1 |

| 1 | 1 | 1 |

| a | b | (a or not b) and (a or not b) |

|---|---|--------------------------------|

| 0 | 0 | 0 |

| 0 | 1 | 0 |

| 1 | 0 | 1 |

| 1 | 1 | 1 |

| a | b | not a or not b |

|---|---|----------------|

| 0 | 0 | 1 |

| 0 | 1 | 1 |

| 1 | 0 | 1 |

| 1 | 1 | 0 |

| a | b | a and (not b or a) and b |

|---|---|------------------------|

| 0 | 0 | 0 |

| 0 | 1 | 0 |

| 1 | 0 | 0 |

| 1 | 1 | 1 |

| a | b | c | a and (b or c) not a |

|---|---|---|---------------------|

| 0 | 0 | 0 | 0 |

| 0 | 0 | 1 | 0 |

| 0 | 1 | 0 | 0 |

| 0 | 1 | 1 | 0 |

| 1 | 0 | 0 | 0 |

| 1 | 0 | 1 | 1 |

| 1 | 1 | 0 | 0 |

| 1 | 1 | 1 | 0 |

| a | b | c | a or b and c or not b |

|---|---|---|-----------------------|

| 0 | 0 | 0 | 0 |

| 0 | 0 | 1 | 1 |

| 0 | 1 | 0 | 0 |

| 0 | 1 | 1 | 1 |

| 1 | 0 | 0 | 1 |

| 1 | 0 | 1 | 1 |

| 1 | 1 | 0 | 1 |

| 1 | 1 | 1 | 1 |