Question

What is the mass of copper (II)-oxide formed as a result of decomposition of 49 g of copper (II)-hydroxide? I can't solve this question, please help​

Answer 1

Ответ:

Объяснение:

To solve this question, you need to first write out the balanced chemical equation for the decomposition of copper (II)-hydroxide:

2Cu(OH)2 → 2CuO + 2H2O

According to the equation, for every 2 moles of copper (II)-hydroxide decomposed, 2 moles of copper (II)-oxide are formed.

Next, you need to convert the given 49 g of copper (II)-hydroxide to moles:

49 g Cu(OH)2 / 97.56 g/mol = 0.502 moles Cu(OH)2

Finally, you can use stoichiometry to find the mass of copper (II)-oxide produced:

0.502 moles Cu(OH)2 x (2 moles CuO / 2 moles Cu(OH)2) x 79.55 g/mol CuO = 39.9 g CuO

Therefore, the mass of copper (II)-oxide formed as a result of the decomposition is approximately 39.9 g.