Question

Розвяжить ривняння
49x^2+51x-100=0

Answer 1

Ответ:

d=2601+4•49•100=✓22201=149

x¹= (-51+149):98=1

x²=(-51-149):98=-200/98≈-2,04

Answer 2

$\displaystyle\bf\\49x^{2} +51x-100=0\\\\D=51^{2} -4\cdot 49\cdot(-100)=2601+19600=22201=149^{2}\\\\\\x_{1} =\frac{-51-149}{49\cdot 2} =\frac{-200}{98} =-2\frac{4}{98} =-2\frac{2}{49} \\\\\\x_{2} =\frac{-51+149}{49\cdot 2} =\frac{98}{98} =1\\\\\\Otvet \ : \ -2\frac{2}{49} \ ; \ 1$