Question

Помогите решить системное уравнение
2x-3(y+1)=2
3(x+1)+3y=2y-1

Answer 1

$2x - 3(y + 1) = 2 \\ 3(x + 1) + 3y = 2y - 1 \\ \\ 2x - 3y - 3 = 2 \\ 3x + 3 + 3y = 2y - 1 \\ \\ 2x - 3y = 2 + 3 \\ 3y - 2y = - 1 - 3 - 3x \\ \\2x - 3( - 3x - 4) = 5 \\ y = - 3x - 4 \\ \\ 2x + 9x + 12 = 5 \\ 11x = 5 - 12 \\ 11x = - 7 \\ x = - \frac{7}{11 } \\ \\ y = - 3 \times ( - \frac{7}{11} ) - 4 = - \frac{21}{11} - 4 = \\ 1 \frac{10}{11} - 4 = 1 \frac{10}{11} - 3 \frac{11}{11} = - 2 \frac{1}{11}$

Ответ: ( - 7/11 ; - 2 1/11 )