Question

ДОПОЖІТЬ БУДЬ ЛАСКА ДУЖЕ ТЕРМІНОВО ДАЮ 50 БАЛІВ!!!!!!!!!!!!!!!!!!​

Answer 1

1)

$(x + 2) {}^{2} = 2x + 3 \\ {x}^{2} + 4x + 4 - 2x - 3 = 0 \\ {x}^{2} + 2x + 1 = 0 \\ (x + 1) {}^{2} = 0 \\ x + 1 = 0 \\ x = - 1$

2)

$5(x - 2) {}^{2} = 3x - 6 \\ 5( {x}^{2} - 4x + 4) = 3x - 6 \\ 5 {x}^{2} -2 0x + 20 - 3x + 6 = 0 \\ 5 {x}^{2} - 23x + 26 = 0 \\ d = ( - 23) {}^{2} - 4 \times 5 \times 26 = \\ 529 - 520 = 9 \\ x_{1} = \frac{23 + 3}{2 \times 5} = \frac{26}{10} = 2.6 \\ x_{2} = \frac{23 - 3}{2 \times 5} = \frac{20}{10} = 2$

3)

$(x + 2)(x - 3) = 2x(x - 4) + 6 \\ {x}^{2} - 3x + 2x - 6 = 2 {x}^{2} - 8x + 6 \\ {x}^{2} - x - 6 -2 {x}^{2} + 8x - 6 = 0 \\ - {x}^{2} + 7x - 12 = \\ {x}^{2} - 7x + 12 = 0 \\ x_{1} + x_{2} =7 \\ x_{1} \times x_{2} = 12 \\ x_{1} =3 \\ x_{2} = 4$