Question

Помогите решить пожалуйста ​

Answer 1

$\frac{7a}{3x {y}^{2} } = \frac{7a \times 5xy}{3x {y}^{2} \times 5xy } = \frac{35axy}{15 {x}^{2} {y}^{3} }$

$\frac{11}{x + 1} = \frac{11(x {}^{2} - x + 1) }{(x + 1)( {x}^{2} - x + 1) } = \frac{11 {x}^{2} - 11x + 11 }{ {x}^{3} + 1 }$