Question

пж пж пж пж пж пж пж ​

Answer 1

Ответ: 1) - 1/2

$y = \ctg( \frac{x}{2} )$

$y ' = \frac{1}{2} \times ( - \frac{1}{ \sin {}^{2} ( \frac{x}{2} ) } ) = - \frac{1}{2 \sin {}^{2} ( \frac{x}{2} ) }$

$y '(\pi) = - \frac{1}{2 \sin {}^{2} ( \frac{\pi}{2} ) } = - \frac{1}{ 2\times 1} = - \frac{1}{2}$