Question

4x ^ 2 + 3|x| - 7 = 0​

Answer 1

Ответ:

4х^2+3х-7=0

4х^2+3(-х)-7=0

4х^2+7х-4х-7=0

х(4х+7)-(4х+7)=0

(4х+7)(х-1)=0

4х+7=0

х-1=0

х= -7/4

х= 1

4х^2-3х-7=0

4х^2+4х-7х-7=0

4х(х+1)-7(х+1)=0

(х+1)(4х-7)=0

х+1=0

4х-7=0

х= -1

х= 7/4

х1=1

х2= -1