Question

СРОЧНО!!!! найдите ошибки и запиши правильное решение​

Answer 1

$\displaystyle\bf\\1)\\\\(4y-3x)(3x+4y)=(4y)^{2} -(3x)^{2} =16y^{2} -9x^{2} \\\\\\2)\\\\100m^{4} -4n^{6}=(10m^{2} )^{2} -(2n^{3} )^{2} =(10m^{2} -2n^{3} )(10m^{2} +2n^{3} )\\\\\\3)\\\\(3x+a)^{2} =(3x)^{2} +2\cdot 3x\cdot a+a^{2} =9x^{2}+6ax+a^{2} \\\\\\4)\\\\(6a^{2} -9c)^{2} =(6a^{2} )^{2} -2\cdot 6a^{2} \cdot 9c+(9c)^{2} =36a^{4} -108a^{2} c+81c^{2}\\\\\\5)\\\\x^{3} +8=x^{3} +2^{3} =(x+2)(x^{2} -2x+4)\\\\\\6)$

$\displaystyle\bf\\(3x+1)^{3} =(3x)^{3} +3\cdot(3x)^{2}\cdot 1+3\cdot 3x\cdot 1^{2} +1^{3} =27x^{3} +27x^{2} +9x+1$