Question

$\sqrt{7-\sqrt{24}}\cdot \sqrt{7+\sqrt{24}}$

Answer 1

Объяснение:

$\sqrt{7 - \sqrt{24} } \times \sqrt{7 + \sqrt{24} } \\ \sqrt{(7 - 2 \sqrt{6} } )(7 + 2 \sqrt{6} ) \\ (a - b)(a + b) = a ^{2} - b ^{2} \\ \sqrt{49 - 4 \times 6} = \sqrt{49 - 24} = \sqrt{25} = 5$